24x^2+53x-7=0

Solution for 24x^2+53x-7=0 equation:

24x^2+53x-7=0

a = 24; b = 53; c = -7;
Δ = b2-4ac
Δ = 532-4·24·(-7)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-59}{2*24}=\frac{-112}{48}
=-2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+59}{2*24}=\frac{6}{48}
=1/8
$